从一个无序,不相等的数组中,选取N个数,使其和为M实现算法(javascript实现)

    function getCombBySum(array,sum,tolerance,targetCount){
      var util = {
        /*
          get combination from array
          arr: target array
          num: combination item length
          return: one array that contain combination arrays
        */
        
        /*获取所有的可能组合
        如果是[1,2,3,4,5]取出3个 
        那么可能性就有10种 C(5,3)= C(5,2) 不懂的恶补高二数学排列😄
        不用翻书了 给个公式 
        全排列  P(n,m)=n!/(n-m)!
        组合排列 C(5,2)=5!/2!*3!=5*4*3*2*1/[(2*1)*(3*2*1)]=10
        这是使用了循环加递归做出了组合排序
        */
        getCombination: function(arr, num) {
          var r=[];
          (function f(t,a,n)
          {
              if (n==0)
              {
                  return r.push(t);
              }
              for (var i=0,l=a.length; i<=l-n; i++)
              {
                  f(t.concat(a[i]), a.slice(i+1), n-1);
              }
          })([],arr,num);
          return r;
        },
        //take array index to a array
        // 获取数组的索引
        getArrayIndex: function(array) {
          var i = 0,
            r = [];
          for(i = 0;i<array.length;i++){
            r.push(i);
          }
          
          return r;
        }
      },logic = {
        //sort the array,then get what's we need
        // 获取数组中比sum小的
        init: function(array,sum) {
          //clone array
          var _array = array.concat(),
          r = [],
          i = 0;
          //sort by asc
          _array.sort(function(a,b){
            return a - b;
          });
          //get all number when it's less than or equal sum
          for(i = 0;i<_array.length;i++){
            if(_array[i]<=sum){
              r.push(_array[i]);
            }else{
              break;
            }
          }
          
          return r;
        },
        //important function
        core: function(array,sum,arrayIndex,count,r){
          var i = 0,
            k = 0,
            combArray = [],
            _sum = 0,
            _cca = [],
            _cache = [];
          
          if(count == _returnMark){
            return;
          }
          //get current count combination
          combArray = util.getCombination(arrayIndex,count);
          for(i = 0;i<combArray.length;i++){
            _cca = combArray[i];
            _sum = 0;
            _cache = [];
            //calculate the sum from combination
            for(k = 0;k<_cca.length;k++){
              _sum += array[_cca[k]];
              _cache.push(array[_cca[k]]);
            }
            if(Math.abs(_sum-sum) <= _tolerance){
              r.push(_cache);
            }      
          }
          
          logic.core(array,sum,arrayIndex,count-1,r);
        }
        
      },
        r = [],
        _array = [],
        _targetCount = 0,
        _tolerance = 0,
        _returnMark = 0;
      
      //check data
      _targetCount = targetCount || _targetCount;
      _tolerance = tolerance || _tolerance;
      
      _array = logic.init(array,sum);
      if(_targetCount){
        _returnMark = _targetCount-1;
      }
      
      logic.core(_array,sum,util.getArrayIndex(_array),(_targetCount || _array.length),r);
      
      return r;
    }
    
    Last Updated: 10/26/2018, 3:27:14 PM